Change of State and Latent Energy – Practice

Questions:

1) How much energy is required to boil 100 mL of water? (Latent heat of vaporization for water = 22.5 × 105 Jkg1):

2) How much energy must be removed from 500 mL of liquid water to freeze it? (Latent heat of fusion for water = 3.34 × 105 Jkg1):

3) 10 gm of ice is placed in 300 mL of water that is at 20°C.

a) How much energy is lost from the water to melt the ice? (Latent heat of fusion for water = 3.34 × 105 Jkg1):

b) What is the final temperature of the glass of water? (The volume will include the ice that melted)

Quick Answers:

1) 22.5 × 104 J

2) 1.67 × 105J 

3a) 3340 J

3b) 19.35°C 

Worked Answers:

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