Change of State and Latent Energy – Practice Questions:1) How much energy is required to boil 100 mL of water? (Latent heat of vaporization for water = 22.5 × 10^{5} Jkg^{–}^{1}):2) How much energy must be removed from 500 mL of liquid water to freeze it? (Latent heat of fusion for water = 3.34 × 10^{5} Jkg^{–}^{1}):3) 10 gm of ice is placed in 300 mL of water that is at 20°C.a) How much energy is lost from the water to melt the ice? (Latent heat of fusion for water = 3.34 × 10^{5} Jkg^{–}^{1}):b) What is the final temperature of the glass of water? (The volume will include the ice that melted) Quick Answers:1) 22.5 × 10^{4} J2) 1.67 × 10^{5}J 3a) 3340 J3b) 19.35°C Worked Answers: